Average Salary by Department

Compute average salary per department from employee records.

averages dictionaries lists salary

Write a function `average_salary_by_dept(employees)` that takes a list of employee records. Each record is a tuple `(name, department, salary)` where `name` is a string, `department` is a string, and `salary` is a number (int or float). The function should return a dictionary where keys are department names and values are the average salary of all employees in that department, rounded to two decimal places. Departments that appear in the input must appear in the output. The order of keys does not matter. If the input list is empty, return an empty dictionary.

Constraints

- 0 <= len(employees) <= 10^5
- Each salary is a finite numeric value (int or float).
- Department names are non-empty strings.
- Average must be rounded to two decimal places using standard rounding.

Example

>>> average_salary_by_dept([("Alice", "Engineering", 90000), ("Bob", "Engineering", 110000), ("Carol", "HR", 70000)])
{'Engineering': 100000.0, 'HR': 70000.0}

10 points ~15 min

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Hints

Use a dictionary to accumulate total salary and count per department.

After collecting totals, compute each department's average by dividing the sum by the count.

Use the round(value, 2) function to round to two decimals.

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