Compare Version Strings

Parse and compare dotted version strings like '1.2.3' against '1.10.0'.

strings parsing comparison

Write a function `compare_versions(v1: str, v2: str) -> int` that compares two version strings and returns:
- `-1` if `v1 < v2`
- `0` if `v1 == v2`
- `1` if `v1 > v2`

A version string consists of one or more numeric components separated by periods (e.g., `"1.2"`, `"1.2.3"`, `"01.2"`). To compare, split each version by `"."` and compare the numeric values of the components from left to right. If one version has fewer components, treat the missing components as `0`.

For example:
- `"1.2"` equals `"1.2.0"`.
- `"1.10"` is greater than `"1.9"`.
- `"01.02"` equals `"1.2"`.

Constraints

- Both version strings contain only digits and periods.
- Each component is a non-negative integer with no leading spaces.
- The number of components is between 1 and 100.
- Each component's integer value fits in a standard Python `int` without overflow.
- You may assume the input strings are well-formed as described.

Example

```python
>>> compare_versions("1.2", "1.10")
-1
>>> compare_versions("1.2", "1.2.0")
0
>>> compare_versions("2.0.1", "1.9.9")
1
```

10 points ~15 min

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Hints

Split each string by '.' and convert each part to int.

Pad the shorter list with zeros to match the longer length.

Compare component by component until you find a difference.

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