Count Positives

Filter a list of numbers and return how many are greater than zero.

conditionals loops basic

Write a function `count_positives(numbers)` that takes a list of integers (or floats) and returns the count of elements that are strictly greater than 0. The input list may be empty. Do not modify the input list. The function should return an integer.

Constraints

- The input list contains at most 10^4 elements.
- Each element is an integer or a float.
- The function should run in O(n) time and O(1) extra space.

Example

>>> count_positives([1, -2, 3, 0, -5])
2
>>> count_positives([0, 0, 0])
0
>>> count_positives([])
0

10 points ~10 min

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Hints

Initialize a counter variable to 0.

Iterate over each number in the list.

Increment the counter when the number is greater than 0.

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