Second node value

Return the second value or None if fewer than two nodes.

linked-list lists pointers

Implement `second_value(values: list)` returning the second payload when it exists.

Constraints

0 ≤ list lengths ≤ 10_000 unless noted.

Example

>>> second_value(...)
# see tests

35 points ~30 min

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Hints

Work on paper with a tiny list first.

Match the function signature exactly.

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