Take n Items

Return a list of the first n items from a list.

slicing list basics

Write a function `take_n(items, n)` that takes a list `items` and a non-negative integer `n` and returns a new list containing the first `n` elements of `items`. If `n` is greater than the length of `items`, return the entire list. If `n` is 0, return an empty list. Your function must not modify the original list.

Constraints

`items` is a list of any type.
`n` is an integer with `0 <= n <= 1000`.
The length of `items` is at most 1000.
The returned list should be a copy of the slice, not a reference to the original.

Example

>>> take_n([10, 20, 30, 40], 2)
[10, 20]
>>> take_n(['a', 'b'], 5)
['a', 'b']
>>> take_n([1, 2, 3], 0)
[]

8 points ~10 min

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Hints

Use list slicing with the colon operator.

Remember that slicing with a stop index larger than the list length automatically stops at the end.

No need to check bounds manually; slicing handles it.

Test Results

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