Toggle a boolean n times

Flip a boolean value exactly n times and return the final state.

booleans arithmetic modulo

Write a function `toggle_bool(value: bool, n: int) -> bool` that returns the result of toggling `value` exactly `n` times. Toggling means: `True` becomes `False`, and `False` becomes `True`. `n` is a non-negative integer. If `n` is 0, the value is unchanged. You may assume `value` is always a boolean.

Implement the function in Python. Do not read input or print output.

Constraints

- `value` is a boolean (`True` or `False`)
- `0 <= n <= 10^9`
- Return a boolean.
- The solution should not use a loop with O(n) time.

Example

>>> bool(toggle_bool(True, 0))
True
>>> bool(toggle_bool(True, 1))
False
>>> bool(toggle_bool(False, 2))
False
>>> bool(toggle_bool(True, 3))
False

6 points ~8 min

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Hints

Toggling twice returns the original value.

Consider the parity of n.

You can use the modulo operator or bitwise XOR.

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