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Algorithms & data structures

Classic patterns — search, sort, stacks, queues, and practical complexity-aware code.

59 matches
Algorithms & data structures easy

Insert an Element Every n Positions in Python

Insert a given element before or after every n-th position in a Python list, returning a new list with the placements applied.

list-manipulation insertion algorithms
Python
def insert_every_n(seq, element, n, position="after"):
    """Insert an element before or after every n-th position in a list.

    Args:
        seq: Input list
        element: Element to insert
        n: Insert every n positions (n > 0)
        position: 'before' or 'after' (default: 'after')
    Returns:
        …
13 0 Open
Algorithms & data structures easy

Move Zeroes to End in Python Maintaining Order

In-place algorithm that moves all zeroes to the end of a list while preserving the relative order of non-zero elements.

two-pointers in-place array
Python
def move_zeroes(nums):
    non_zero_index = 0
    for i in range(len(nums)):
        if nums[i] != 0:
            nums[non_zero_index], nums[i] = nums[i], nums[non_zero_index]
            non_zero_index += 1
    return nums

if __name__ == "__main__":
    example = [0, 1, 0, 3, 12]
    result = move_zeroes(example)
  …
14 0 Open
Algorithms & data structures easy

Pair Elements with Next Cyclic Neighbor in Python

Create tuples pairing every element with its next element, wrapping around to the first element for the last one.

pairs cyclic list
Python
def cyclic_pairs(lst):
    if not lst:
        return []
    return [(lst[i], lst[(i + 1) % len(lst)]) for i in range(len(lst))]


if __name__ == "__main__":
    sample = [1, 2, 3, 4, 5]
    result = cyclic_pairs(sample)
    print(result)
15 0 Open
Algorithms & data structures easy

Rearrange array alternately max min in Python

Rearranges a sorted list so its elements alternate between the current maximum and current minimum using two pointers in O(n) time.

two-pointers array sorting
Python
def rearrange_alternately(arr):
    """
    Rearrange sorted array so elements alternate: max, min, next max, next min...
    Returns a new list in O(n) time using O(n) space.
    """
    n = len(arr)
    result = []
    left, right = 0, n - 1
    while left <= right:
        if left == right:
            result.appen…
14 0 Open
Algorithms & data structures easy

Remove item at index without pop in Python

Remove an item at a given index from a list without using pop by slicing the list around the index.

list slicing algorithms
Python
def remove_at_index(lst, index):
    """Remove item at index and return the new list."""
    if index < 0 or index >= len(lst):
        raise IndexError("Index out of range")
    return lst[:index] + lst[index + 1:]


if __name__ == "__main__":
    items = [10, 20, 30, 40, 50]
    result = remove_at_index(items, 2)
  …
12 0 Open
Algorithms & data structures easy

Reorder a List by Odd Even Indices in Python

Splits a list into two sublists based on 1-based index parity, then concatenates odd-indexed elements before even-indexed ones.

list indices reorder
Python
def reorder_by_odd_even(items):
    """Reorders a list so that elements at odd indices come first,
    followed by elements at even indices (1-based).
    
    Example: [0,1,2,3,4,5,6] -> [1,3,5,0,2,4,6]
    """
    odds = [items[i] for i in range(1, len(items), 2)]
    evens = [items[i] for i in range(0, len(items), …
18 0 Open
Algorithms & data structures easy

Segregate Negative Numbers Before Positives in Python

Reorders a list so all negative numbers appear before non-negative numbers while preserving the original relative order of elements.

lists partition stability
Python
def segregate_negatives(numbers):
    """Segregate negatives before positives without altering relative order."""
    negatives = [n for n in numbers if n < 0]
    positives = [n for n in numbers if n >= 0]
    return negatives + positives


if __name__ == "__main__":
    sample = [3, -1, 4, -5, 2, -9, 0]
    result =…
14 0 Open
Algorithms & data structures easy

Sort Unique Values by Frequency in Python

Count element frequencies with Counter and sort unique values by descending frequency, breaking ties alphabetically.

counter sorting frequency
Python
from collections import Counter

def sort_unique_by_frequency(values):
    counts = Counter(values)
    return sorted(counts.keys(), key=lambda x: (-counts[x], x))

if __name__ == "__main__":
    data = [4, 2, 2, 8, 3, 3, 1, 3, 5, 5, 5, 5, 1]
    result = sort_unique_by_frequency(data)
    print(f"Sorted unique values…
12 0 Open
Algorithms & data structures easy

Sort list by multiple keys with tuple ordering in Python

Sort a list of dictionaries by multiple criteria — surname, age, then score descending — using a tuple key and negation.

sorting tuples lambda
Python
def sort_multi_key(data):
    # Sorts by surname, then age, then score descending
    return sorted(
        data,
        key=lambda person: (
            person['surname'].lower(),
            person['age'],
            -person['score']  # negative to reverse sort by score
        )
    )


if __name__ == "__main__"…
14 0 Open
Algorithms & data structures easy

Stable sort preserving equal order demo in Python

Demonstrates Python's stable sort, showing that elements with equal sort keys retain their original relative order.

sorting stable sort timsort
Python
from operator import itemgetter

def stable_sort_demo():
    data = [(3, "first"), (1, "second"), (3, "third"), (1, "fourth"), (2, "fifth")]
    print("Original:", data)
    
    # Sort by first element (the tuple's first value), keeping relative order of equal items
    sorted_data = sorted(data, key=itemgetter(0))
 …
13 0 Open
Algorithms & data structures easy

Take While Predicate True From Start in Python

Create a custom take_while function that collects elements from an iterable until a predicate returns False, then stops.

takewhile iteration predicate
Python
def take_while(predicate, iterable):
    """Return elements from iterable until the predicate becomes False."""
    result = []
    for item in iterable:
        if predicate(item):
            result.append(item)
        else:
            break
    return result


if __name__ == "__main__":
    numbers = [2, 4, 6, 7,…
13 0 Open

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