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Algorithms & data structures

Classic patterns — search, sort, stacks, queues, and practical complexity-aware code.

18 matches
Algorithms & data structures medium

Binary Search for Ship Capacity in Python

Use binary search to find the minimum ship capacity that can transport all packages within a given number of days.

binary search greedy capacity
Python
def ship_within_days(weights, days):
    def can_ship(capacity):
        current = 0
        needed_days = 1
        for weight in weights:
            if current + weight > capacity:
                needed_days += 1
                current = 0
            current += weight
        return needed_days <= days

    low …
13 0 Open
Algorithms & data structures medium

Find Longest Increasing Subsequence Length in Python

Compute the length of the longest increasing subsequence in an array using dynamic programming.

dynamic-programming subsequence algorithm
Python
def longest_increasing_subsequence(nums):
    if not nums:
        return 0
    
    dp = [1] * len(nums)
    
    for i in range(1, len(nums)):
        for j in range(i):
            if nums[i] > nums[j]:
                dp[i] = max(dp[i], dp[j] + 1)
    
    return max(dp)

if __name__ == "__main__":
    # Demo with…
15 0 Open
Algorithms & data structures medium

Find Peak Element in Python Using Binary Search

A binary search solution that finds any peak element (an element strictly greater than its neighbors) in an unsorted array in O(log n) time.

binary-search peak array
Python
def find_peak_element(nums):
    left, right = 0, len(nums) - 1
    
    while left < right:
        mid = (left + right) // 2
        if nums[mid] > nums[mid + 1]:
            right = mid
        else:
            left = mid + 1
            
    return left

if __name__ == "__main__":
    test1 = [1, 2, 3, 1]
    tes…
17 0 Open
Algorithms & data structures medium

Find the Majority Element in Python with Boyer-Moore Vote

Use Boyer-Moore majority vote to find the element appearing more than n/2 times in an array in O(n) time and O(1) space.

boyer-moore majority-element array
Python
def majority_element(nums):
    candidate = None
    count = 0

    for num in nums:
        if count == 0:
            candidate = num
        count += 1 if num == candidate else -1

    return candidate

if __name__ == "__main__":
    nums = [2, 2, 1, 1, 1, 2, 2]
    result = majority_element(nums)
    print(f"Major…
14 0 Open
Algorithms & data structures medium

Find two unique numbers in an array with Python

Returns the two numbers that appear exactly once in a list where every other number appears twice, using XOR bit manipulation.

bit-manipulation xor arrays
Python
def find_two_odd(arr):
    """Return the two numbers that appear exactly once, while all others appear twice."""
    xor_all = 0
    for num in arr:
        xor_all ^= num

    # xor_all now equals the XOR of the two unique numbers.
    # Find a set bit (any bit where they differ).
    diff_bit = xor_all & (-xor_all)
…
13 0 Open
Algorithms & data structures medium

Game of Life Next State Grid in Python

Compute the next generation of Conway's Game of Life from a 2D grid using the standard three rules with neighbor counting.

game-of-life grid cellular-automaton
Python
def next_state(grid):
    m, n = len(grid), len(grid[0])
    new = [[0] * n for _ in range(m)]
    for r in range(m):
        for c in range(n):
            total = 0
            for dr in (-1, 0, 1):
                for dc in (-1, 0, 1):
                    if dr == 0 and dc == 0:
                        continue
   …
14 0 Open
Algorithms & data structures medium

How to Decode a String with Repeated Brackets in Python

Decodes strings with patterns like '3[a]2[bc]' by using a stack to handle nested and repeated bracket groups.

stack string-decoding algorithms
Python
def decode_string(s: str) -> str:
    stack = []
    current_num = 0
    current_str = ""

    for ch in s:
        if ch.isdigit():
            current_num = current_num * 10 + int(ch)
        elif ch == "[":
            stack.append((current_str, current_num))
            current_str = ""
            current_num = 0…
13 0 Open
Algorithms & data structures medium

How to Detect Hardcoded Secrets in Python Source Code

A Python utility that scans source code for common hardcoded secrets like API keys, passwords, tokens, and AWS credentials using regex patterns.

secrets regex security
Python
import re

def detect_secrets(text):
    """Detect potential hardcoded secrets in source code."""
    patterns = {
        'api_key': r'(?i)(api[_-]?key|apikey)\s*[=:]\s*["\']([^"\']+)["\']',
        'password': r'(?i)(password|passwd)\s*[=:]\s*["\']([^"\']+)["\']',
        'token': r'(?i)(\b(token|secret)\b)\s*[=:]\s…
43 0 Open
Algorithms & data structures medium

How to Evaluate RPN Expressions in Python

Use a stack to evaluate Reverse Polish Notation token lists with a dictionary of operator lambdas, truncating division toward zero.

rpn stack expression
Python
def eval_rpn(tokens):
    stack = []
    ops = {
        '+': lambda a, b: a + b,
        '-': lambda a, b: a - b,
        '*': lambda a, b: a * b,
        '/': lambda a, b: int(a / b)  # truncate toward zero
    }
    for token in tokens:
        if token in ops:
            b = stack.pop()
            a = stack.pop(…
12 0 Open
Algorithms & data structures medium

How to Find Minimum Swaps to Sort an Array in Python

Calculate the minimum number of adjacent-free swaps needed to sort a permutation array using cycle detection in Python.

sorting cycles greedy
Python
def min_swaps_to_sort(arr):
    n = len(arr)
    arr_pos = sorted((val, idx) for idx, val in enumerate(arr))
    visited = [False] * n
    swaps = 0

    for i in range(n):
        if visited[i] or arr_pos[i][1] == i:
            continue

        cycle_size = 0
        j = i
        while not visited[j]:
            …
13 0 Open
Algorithms & data structures medium

How to Find the Next Greater Element for Each List Item in Python

Use a monotonic stack to find the next greater element to the right for every item in a list, in O(n) time.

stack monotonic stack algorithm
Python
def next_greater_element(nums):
    result = [-1] * len(nums)
    stack = []
    
    for i in range(len(nums) - 1, -1, -1):
        while stack and stack[-1] <= nums[i]:
            stack.pop()
        result[i] = stack[-1] if stack else -1
        stack.append(nums[i])
    
    return result


if __name__ == "__main…
13 0 Open
Algorithms & data structures medium

How to Find the Previous Smaller Element in Python

Use a monotonic stack to find the nearest smaller element to the left of each item in a list, returning -1 when none exists.

monotonic stack stack arrays
Python
from collections import deque

def previous_smaller_elements(arr):
    stack = deque()
    result = [-1] * len(arr)

    for i in range(len(arr)):
        while stack and arr[stack[-1]] >= arr[i]:
            stack.pop()
        if stack:
            result[i] = arr[stack[-1]]
        stack.append(i)

    return resul…
15 0 Open
Algorithms & data structures medium

How to Search a Rotated Sorted List in Python

Binary search a pivot-rotated sorted list for a target value and return its index in O(log n) time.

binary-search rotated-array search-algorithm
Python
from typing import List

def search_rotated(nums: List[int], target: int) -> int:
    left, right = 0, len(nums) - 1

    while left <= right:
        mid = (left + right) // 2
        if nums[mid] == target:
            return mid

        # left half is sorted
        if nums[left] <= nums[mid]:
            if nums[…
12 0 Open
Algorithms & data structures medium

How to Solve Daily Temperatures Days Until Warmer in Python

Compute the number of days until a warmer temperature for each day using a monotonic stack.

stack monotonic algorithm
Python
def daily_temperatures(temps):
    n = len(temps)
    result = [0] * n
    stack = []
    
    for i, temp in enumerate(temps):
        while stack and temps[stack[-1]] < temp:
            prev_idx = stack.pop()
            result[prev_idx] = i - prev_idx
        stack.append(i)
    
    return result

if __name__ == …
12 0 Open
Algorithms & data structures medium

Implement Insert Delete GetRandom O(1) in Python

Build a RandomizedSet class that supports insert, delete, and get_random in average O(1) time using a list and a dictionary mapping values to indices.

randomized-set o1-lookup hash-map
Python
import random

class RandomizedSet:
    def __init__(self):
        self.values = []
        self.index_map = {}

    def insert(self, val):
        if val in self.index_map:
            return False
        self.index_map[val] = len(self.values)
        self.values.append(val)
        return True

    def delete(self…
12 0 Open
Algorithms & data structures medium

Product of All Elements Except Self in Python

Given a list of integers, return a list where each element is the product of all other elements except itself, using prefix and suffix products in O(n) time and O(1) extra space.

array prefix suffix
Python
def product_except_self(nums):
    n = len(nums)
    result = [1] * n
    
    left_product = 1
    for i in range(n):
        result[i] = left_product
        left_product *= nums[i]
    
    right_product = 1
    for i in range(n - 1, -1, -1):
        result[i] *= right_product
        right_product *= nums[i]
    
…
14 0 Open
Algorithms & data structures medium

Product of Array Except Self in Python Without Division

Compute the product of all array elements except the current one in O(n) time using prefix and suffix products, without using division.

arrays prefix-product suffix-product
Python
from math import prod


def product_except_self(nums):
    n = len(nums)
    result = [1] * n
    left_product = 1
    for i in range(n):
        result[i] = left_product
        left_product *= nums[i]

    right_product = 1
    for i in range(n - 1, -1, -1):
        result[i] *= right_product
        right_product *…
14 0 Open
Algorithms & data structures medium

Split Array Largest Sum in Python (Minimize Largest Subarray Sum)

Binary search + greedy check to split an array into k subarrays while minimizing the largest subarray sum.

binary-search greedy array
Python
def can_split(nums, k, max_sum):
    subarrays = 1
    current_sum = 0
    for num in nums:
        if current_sum + num <= max_sum:
            current_sum += num
        else:
            subarrays += 1
            current_sum = num
            if subarrays > k:
                return False
    return True

def spli…
15 0 Open

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