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Algorithms & data structures

Classic patterns — search, sort, stacks, queues, and practical complexity-aware code.

4 matches
Algorithms & data structures medium

Find the Duplicate Number in Python Using Floyd's Cycle Detection

Detects the duplicate integer in an array of n+1 numbers (values 1 to n) in O(n) time and O(1) space using Floyd's cycle detection algorithm applied to a linked-list model.

floyd-cycle duplicate-number two-pointers
Python
def find_duplicate(nums):
    slow = nums[0]
    fast = nums[0]
    
    # Phase 1: Find intersection point of the cycle
    while True:
        slow = nums[slow]
        fast = nums[nums[fast]]
        if slow == fast:
            break
    
    # Phase 2: Find the start of the cycle (the duplicate)
    slow = nums[0…
14 0 Open
Algorithms & data structures medium

How to Detect Hardcoded Secrets in Python Source Code

A Python utility that scans source code for common hardcoded secrets like API keys, passwords, tokens, and AWS credentials using regex patterns.

secrets regex security
Python
import re

def detect_secrets(text):
    """Detect potential hardcoded secrets in source code."""
    patterns = {
        'api_key': r'(?i)(api[_-]?key|apikey)\s*[=:]\s*["\']([^"\']+)["\']',
        'password': r'(?i)(password|passwd)\s*[=:]\s*["\']([^"\']+)["\']',
        'token': r'(?i)(\b(token|secret)\b)\s*[=:]\s…
43 0 Open
Algorithms & data structures easy

How to Find Gaps Between Sorted Intervals in Python

This code finds gap ranges between sorted intervals using pairwise iteration, returning ranges where no interval covers.

intervals pairwise sorting
Python
from itertools import pairwise

def find_gaps(intervals):
    intervals = sorted(intervals)
    gaps = []
    for prev, curr in pairwise(intervals):
        if prev[1] < curr[0]:
            gaps.append((prev[1] + 1, curr[0] - 1))
    return gaps

if __name__ == "__main__":
    intervals = [(1, 3), (5, 7), (10, 12), (…
14 0 Open
Algorithms & data structures medium

How to Find Minimum Swaps to Sort an Array in Python

Calculate the minimum number of adjacent-free swaps needed to sort a permutation array using cycle detection in Python.

sorting cycles greedy
Python
def min_swaps_to_sort(arr):
    n = len(arr)
    arr_pos = sorted((val, idx) for idx, val in enumerate(arr))
    visited = [False] * n
    swaps = 0

    for i in range(n):
        if visited[i] or arr_pos[i][1] == i:
            continue

        cycle_size = 0
        j = i
        while not visited[j]:
            …
13 0 Open

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