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Algorithms & data structures

Classic patterns — search, sort, stacks, queues, and practical complexity-aware code.

11 matches
Algorithms & data structures easy

Find Longest Consecutive Run in an Unsorted List in Python

Find the length of the longest sequence of consecutive integers in an unsorted list using a set and a linear scan.

set consecutive linear-scan
Python
def longest_run(nums):
    if not nums:
        return 0

    num_set = set(nums)
    longest = 0

    for num in num_set:
        # Only start counting from the smallest number in a sequence
        if num - 1 not in num_set:
            current = num
            length = 1
            while current + 1 in num_set:
 …
11 0 Open
Algorithms & data structures medium

Find Longest Consecutive Sequence in Python

Find the length of the longest consecutive elements sequence in an unsorted array using a set for O(n) lookups.

set longest-sequence hash-table
Python
def longest_consecutive_length(nums):
    num_set = set(nums)
    longest = 0
    
    for num in num_set:
        if num - 1 not in num_set:
            current = num
            current_streak = 1
            
            while current + 1 in num_set:
                current += 1
                current_streak += 1
…
13 0 Open
Algorithms & data structures medium

Find Longest Increasing Subsequence Length in Python

Compute the length of the longest increasing subsequence in an array using dynamic programming.

dynamic-programming subsequence algorithm
Python
def longest_increasing_subsequence(nums):
    if not nums:
        return 0
    
    dp = [1] * len(nums)
    
    for i in range(1, len(nums)):
        for j in range(i):
            if nums[i] > nums[j]:
                dp[i] = max(dp[i], dp[j] + 1)
    
    return max(dp)

if __name__ == "__main__":
    # Demo with…
15 0 Open
Algorithms & data structures easy

Find Median of Two Sorted Arrays in Python

Merges two sorted arrays with a two-pointer walk and returns the median of the combined sorted sequence.

median two-pointer merge
Python
def median_of_two_sorted_arrays(nums1, nums2):
    merged = []
    i = j = 0
    while i < len(nums1) and j < len(nums2):
        if nums1[i] <= nums2[j]:
            merged.append(nums1[i])
            i += 1
        else:
            merged.append(nums2[j])
            j += 1
    merged.extend(nums1[i:])
    merged.…
15 0 Open
Algorithms & data structures easy

Find Missing Number in Python Sequence 1 to N

Find the missing number from a list containing numbers 1 to N using the arithmetic sum formula.

missing-number arithmetic sum
Python
def find_missing_number(nums, n):
    expected_sum = n * (n + 1) // 2
    actual_sum = sum(nums)
    return expected_sum - actual_sum


if __name__ == "__main__":
    n = 10
    numbers = [1, 2, 3, 4, 5, 6, 7, 9, 10]
    missing = find_missing_number(numbers, n)
    print(f"The missing number is: {missing}")
15 0 Open
Algorithms & data structures easy

Find the Last Index Where a Condition Is True in Python

This code scans a sequence from the end and returns the index of the last element that satisfies a given condition, or -1 if none do.

search list reverse
Python
def last_index_where(sequence, condition):
    """Return the index of the last element in sequence that satisfies condition."""
    for i in range(len(sequence) - 1, -1, -1):
        if condition(sequence[i]):
            return i
    return -1

if __name__ == "__main__":
    numbers = [1, 4, 7, 2, 9, 5, 8, 3]
    is_…
12 0 Open
Algorithms & data structures easy

How to Generate Fibonacci Sequence in Python

Generate the first n Fibonacci numbers as a list using a simple iterative loop.

fibonacci sequences iteration
Python
def fibonacci(n):
    """Generate the first n terms of the Fibonacci sequence."""
    if n <= 0:
        return []
    seq = [0, 1]
    while len(seq) < n:
        seq.append(seq[-1] + seq[-2])
    return seq[:n]

if __name__ == "__main__":
    n = 10
    result = fibonacci(n)
    print(result)
13 0 Open
Algorithms & data structures easy

How to Generate a Geometric Progression List in Python

This Python function builds a list of n terms in a geometric progression, starting with a given first term and multiplying by a constant ratio at each step.

geometric-progression sequence algorithms
Python
def geometric_progression(first_term, ratio, count):
    """
    Generate a list of 'count' terms in a geometric progression
    starting with 'first_term' and multiplied by 'ratio' each step.
    """
    progression = []
    current = first_term
    for _ in range(count):
        progression.append(current)
        c…
13 0 Open
Algorithms & data structures easy

How to Generate an Arithmetic Progression List in Python

Generates a list of terms in an arithmetic progression using a list comprehension.

arithmetic list-comprehension sequences
Python
def generate_ap(start, difference, count):
    """Generate a list of n terms in an arithmetic progression."""
    return [start + i * difference for i in range(count)]


if __name__ == "__main__":
    ap = generate_ap(3, 5, 6)
    print(ap)
14 0 Open
Algorithms & data structures easy

How to Sample Random Items Without Replacement in Python

Select k random unique items from a sequence using random.sample for uniform, non-repeating selection.

random sampling algorithms
Python
import random

def sample_without_replacement(population, k):
    """Return k random items from population without replacement."""
    if k > len(population):
        raise ValueError("k cannot exceed population size")
    # Use random.sample for O(k) time, no mutation of the original
    return random.sample(populati…
15 0 Open
Algorithms & data structures easy

Insert an Element Every n Positions in Python

Insert a given element before or after every n-th position in a Python list, returning a new list with the placements applied.

list-manipulation insertion algorithms
Python
def insert_every_n(seq, element, n, position="after"):
    """Insert an element before or after every n-th position in a list.

    Args:
        seq: Input list
        element: Element to insert
        n: Insert every n positions (n > 0)
        position: 'before' or 'after' (default: 'after')
    Returns:
        …
13 0 Open

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